3.2654 \(\int \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{3/2} \, dx\)

Optimal. Leaf size=191 \[ -\frac {160297 \sqrt {\frac {11}{3}} \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{708750}+\frac {2}{45} \sqrt {1-2 x} (3 x+2)^{3/2} (5 x+3)^{5/2}-\frac {3}{175} \sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{5/2}-\frac {1208 \sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{3/2}}{7875}-\frac {160297 \sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}{141750}-\frac {5327983 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{708750} \]

[Out]

-5327983/2126250*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-160297/2126250*EllipticF(1/7*2
1^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)+2/45*(2+3*x)^(3/2)*(3+5*x)^(5/2)*(1-2*x)^(1/2)-1208/7875*(3+5*
x)^(3/2)*(1-2*x)^(1/2)*(2+3*x)^(1/2)-3/175*(3+5*x)^(5/2)*(1-2*x)^(1/2)*(2+3*x)^(1/2)-160297/141750*(1-2*x)^(1/
2)*(2+3*x)^(1/2)*(3+5*x)^(1/2)

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Rubi [A]  time = 0.07, antiderivative size = 191, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {101, 154, 158, 113, 119} \[ \frac {2}{45} \sqrt {1-2 x} (3 x+2)^{3/2} (5 x+3)^{5/2}-\frac {3}{175} \sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{5/2}-\frac {1208 \sqrt {1-2 x} \sqrt {3 x+2} (5 x+3)^{3/2}}{7875}-\frac {160297 \sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}{141750}-\frac {160297 \sqrt {\frac {11}{3}} F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{708750}-\frac {5327983 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{708750} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*(3 + 5*x)^(3/2),x]

[Out]

(-160297*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*Sqrt[3 + 5*x])/141750 - (1208*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*(3 + 5*x)^(3/2)
)/7875 - (3*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*(3 + 5*x)^(5/2))/175 + (2*Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*(3 + 5*x)^(5/2
))/45 - (5327983*Sqrt[11/3]*EllipticE[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/708750 - (160297*Sqrt[11/3]*Ell
ipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/708750

Rule 101

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a +
b*x)^m*(c + d*x)^n*(e + f*x)^(p + 1))/(f*(m + n + p + 1)), x] - Dist[1/(f*(m + n + p + 1)), Int[(a + b*x)^(m -
1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[c*m*(b*e - a*f) + a*n*(d*e - c*f) + (d*m*(b*e - a*f) + b*n*(d*e - c*f))
*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && GtQ[m, 0] && GtQ[n, 0] && NeQ[m + n + p + 1, 0] && (Integ
ersQ[2*m, 2*n, 2*p] || (IntegersQ[m, n + p] || IntegersQ[p, m + n]))

Rule 113

Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-((b*e
- a*f)/d), 2]*EllipticE[ArcSin[Sqrt[a + b*x]/Rt[-((b*c - a*d)/d), 2]], (f*(b*c - a*d))/(d*(b*e - a*f))])/b, x
] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !LtQ[-((b*c - a*d)/d),
0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-(d/(b*c - a*d)), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)
/b, 0])

Rule 119

Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-(b/d
), 2]*EllipticF[ArcSin[Sqrt[a + b*x]/(Rt[-(b/d), 2]*Sqrt[(b*c - a*d)/b])], (f*(b*c - a*d))/(d*(b*e - a*f))])/(
b*Sqrt[(b*e - a*f)/b]), x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ[(b*e - a*f)/b, 0] &
& PosQ[-(b/d)] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d*e - c*f)/d, 0] && GtQ[-(d/b), 0]) &&  !(SimplerQ[c +
d*x, a + b*x] && GtQ[(-(b*e) + a*f)/f, 0] && GtQ[-(f/b), 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ[(-(d*e)
+ c*f)/f, 0] && GtQ[(-(b*e) + a*f)/f, 0] && (PosQ[-(f/d)] || PosQ[-(f/b)]))

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 158

Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol]
:> Dist[h/f, Int[Sqrt[e + f*x]/(Sqrt[a + b*x]*Sqrt[c + d*x]), x], x] + Dist[(f*g - e*h)/f, Int[1/(Sqrt[a + b*
x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && SimplerQ[a + b*x, e + f*x] &&
SimplerQ[c + d*x, e + f*x]

Rubi steps

\begin {align*} \int \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{3/2} \, dx &=\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}-\frac {2}{45} \int \frac {\left (-\frac {25}{2}-\frac {27 x}{2}\right ) \sqrt {2+3 x} (3+5 x)^{3/2}}{\sqrt {1-2 x}} \, dx\\ &=-\frac {3}{175} \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}+\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}+\frac {2 \int \frac {(3+5 x)^{3/2} \left (\frac {4769}{4}+1812 x\right )}{\sqrt {1-2 x} \sqrt {2+3 x}} \, dx}{1575}\\ &=-\frac {1208 \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{3/2}}{7875}-\frac {3}{175} \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}+\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}-\frac {2 \int \frac {\left (-\frac {312453}{4}-\frac {480891 x}{4}\right ) \sqrt {3+5 x}}{\sqrt {1-2 x} \sqrt {2+3 x}} \, dx}{23625}\\ &=-\frac {160297 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{141750}-\frac {1208 \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{3/2}}{7875}-\frac {3}{175} \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}+\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}+\frac {2 \int \frac {\frac {20238699}{8}+\frac {15983949 x}{4}}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{212625}\\ &=-\frac {160297 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{141750}-\frac {1208 \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{3/2}}{7875}-\frac {3}{175} \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}+\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}+\frac {1763267 \int \frac {1}{\sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}} \, dx}{1417500}+\frac {5327983 \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x} \sqrt {2+3 x}} \, dx}{708750}\\ &=-\frac {160297 \sqrt {1-2 x} \sqrt {2+3 x} \sqrt {3+5 x}}{141750}-\frac {1208 \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{3/2}}{7875}-\frac {3}{175} \sqrt {1-2 x} \sqrt {2+3 x} (3+5 x)^{5/2}+\frac {2}{45} \sqrt {1-2 x} (2+3 x)^{3/2} (3+5 x)^{5/2}-\frac {5327983 \sqrt {\frac {11}{3}} E\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{708750}-\frac {160297 \sqrt {\frac {11}{3}} F\left (\sin ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{708750}\\ \end {align*}

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Mathematica [A]  time = 0.32, size = 102, normalized size = 0.53 \[ \frac {-5366165 \operatorname {EllipticF}\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right ),-\frac {33}{2}\right )+15 \sqrt {2-4 x} \sqrt {3 x+2} \sqrt {5 x+3} \left (472500 x^3+821250 x^2+366480 x-133999\right )[phone] E\left (\sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )|-\frac {33}{2}\right )}{2126250 \sqrt {2}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*(3 + 5*x)^(3/2),x]

[Out]

(15*Sqrt[2 - 4*x]*Sqrt[2 + 3*x]*Sqrt[3 + 5*x]*(-133999 + 366480*x + 821250*x^2 + 472500*x^3) + 10655966*Ellipt
icE[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2] - 5366165*EllipticF[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2])/(21
26250*Sqrt[2])

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fricas [F]  time = 0.92, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (15 \, x^{2} + 19 \, x + 6\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(3/2)*(3+5*x)^(3/2)*(1-2*x)^(1/2),x, algorithm="fricas")

[Out]

integral((15*x^2 + 19*x + 6)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (5 \, x + 3\right )}^{\frac {3}{2}} {\left (3 \, x + 2\right )}^{\frac {3}{2}} \sqrt {-2 \, x + 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(3/2)*(3+5*x)^(3/2)*(1-2*x)^(1/2),x, algorithm="giac")

[Out]

integrate((5*x + 3)^(3/2)*(3*x + 2)^(3/2)*sqrt(-2*x + 1), x)

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maple [C]  time = 0.01, size = 155, normalized size = 0.81 \[ \frac {\sqrt {3 x +2}\, \sqrt {5 x +3}\, \sqrt {-2 x +1}\, \left (425250000 x^{6}[phone] x^{5}[phone] x^{4}-125240400 x^{3}-317245110 x^{2}-37826610 x -10655966 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticE \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )+5366165 \sqrt {2}\, \sqrt {5 x +3}\, \sqrt {3 x +2}\, \sqrt {-2 x +1}\, \EllipticF \left (\frac {\sqrt {110 x +66}}{11}, \frac {i \sqrt {66}}{2}\right )[phone]\right )}{127575000 x^{3}[phone] x^{2}-29767500 x -25515000} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^(3/2)*(5*x+3)^(3/2)*(-2*x+1)^(1/2),x)

[Out]

1/4252500*(3*x+2)^(1/2)*(5*x+3)^(1/2)*(-2*x+1)^(1/2)*(425250000*x^6+5366165*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2
)*(-2*x+1)^(1/2)*EllipticF(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))-10655966*2^(1/2)*(5*x+3)^(1/2)*(3*x+2)^(1/2)*
(-2*x+1)^(1/2)*EllipticE(1/11*(110*x+66)^(1/2),1/2*I*66^(1/2))[phone]*x^5+797269500*x^4-125240400*x^3-3172
45110*x^2-37826610*x+24119820)/(30*x^3+23*x^2-7*x-6)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (5 \, x + 3\right )}^{\frac {3}{2}} {\left (3 \, x + 2\right )}^{\frac {3}{2}} \sqrt {-2 \, x + 1}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(3/2)*(3+5*x)^(3/2)*(1-2*x)^(1/2),x, algorithm="maxima")

[Out]

integrate((5*x + 3)^(3/2)*(3*x + 2)^(3/2)*sqrt(-2*x + 1), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \sqrt {1-2\,x}\,{\left (3\,x+2\right )}^{3/2}\,{\left (5\,x+3\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(1/2)*(3*x + 2)^(3/2)*(5*x + 3)^(3/2),x)

[Out]

int((1 - 2*x)^(1/2)*(3*x + 2)^(3/2)*(5*x + 3)^(3/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**(3/2)*(3+5*x)**(3/2)*(1-2*x)**(1/2),x)

[Out]

Timed out

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